(2x^2-4x-2)+(2y^2+4y+2)=2

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Solution for (2x^2-4x-2)+(2y^2+4y+2)=2 equation:


Simplifying
(2x2 + -4x + -2) + (2y2 + 4y + 2) = 2

Reorder the terms:
(-2 + -4x + 2x2) + (2y2 + 4y + 2) = 2

Remove parenthesis around (-2 + -4x + 2x2)
-2 + -4x + 2x2 + (2y2 + 4y + 2) = 2

Reorder the terms:
-2 + -4x + 2x2 + (2 + 4y + 2y2) = 2

Remove parenthesis around (2 + 4y + 2y2)
-2 + -4x + 2x2 + 2 + 4y + 2y2 = 2

Reorder the terms:
-2 + 2 + -4x + 2x2 + 4y + 2y2 = 2

Combine like terms: -2 + 2 = 0
0 + -4x + 2x2 + 4y + 2y2 = 2
-4x + 2x2 + 4y + 2y2 = 2

Solving
-4x + 2x2 + 4y + 2y2 = 2

Solving for variable 'x'.

Reorder the terms:
-2 + -4x + 2x2 + 4y + 2y2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -4x + 2x2 + 4y + 2y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-1 + -2x + x2 + 2y + y2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-1 + -2x + x2 + 2y + y2)' equal to zero and attempt to solve: Simplifying -1 + -2x + x2 + 2y + y2 = 0 Solving -1 + -2x + x2 + 2y + y2 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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